2x^(4/3)-5x^(2/3)+2=0

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Solution for 2x^(4/3)-5x^(2/3)+2=0 equation: 


x in (-oo:+oo)

2*x^(4/3)-(5*x^(2/3))+2 = 0

2*x^(4/3)-5*x^(2/3)+2 = 0

t_1 = x^(2/3)

2*t_1^2-5*t_1^1+2 = 0

2*t_1^2-5*t_1+2 = 0

DELTA = (-5)^2-(2*2*4)

DELTA = 9

DELTA > 0

t_1 = (9^(1/2)+5)/(2*2) or t_1 = (5-9^(1/2))/(2*2)

t_1 = 2 or t_1 = 1/2

t_1 = 1/2

x^(2/3)-1/2 = 0

1*x^(2/3) = 1/2 // : 1

x^(2/3) = 1/2

x^(2/3) = 1/2 // ^ 3

x^2 = 1/8 // ^ 1/2

abs(x) = (1/8)^(1/2)

x = (1/8)^(1/2) or x = -(1/8)^(1/2)

t_1 = 2

x^(2/3)-2 = 0

1*x^(2/3) = 2 // : 1

x^(2/3) = 2

x^(2/3) = 2 // ^ 3

x^2 = 8 // ^ 1/2

abs(x) = 2*2^(1/2)

x = 2*2^(1/2) or x = -(2*2^(1/2))

x in { (1/8)^(1/2), -(1/8)^(1/2), 2*2^(1/2), -(2*2^(1/2)) }

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